Hmm? Are you sure you modeled the 10"? I have never used WinISD before, but I entered the driver data into it and it says Q of .703 = 1.098 cu ft. sealed. Now, subract 25% of that volume for 100% stuffing = .82 cu ft. (+ air displaced by driver itself). Is this wrong? How do I determine how much air the driver is displacing? Thanks for all the help!The RSS265HF-4 has a Q of .7 at 3 cu.ft. Assuming 100% stuffing equals a 25% increase, then the box would be 2.4 cu.ft. Add whatever the displacement of the sub is to that and you have the total internal volume.
Are they just recommending 1 cu. ft. sealed or are they saying 1.cu. ft. is a Q of .7?It seems that other sites also recommend 1 cu ft sealed for this driver too
Re is listed as 4.4 ohms in the file as stated from the parameters. Any small differences are from the auto calculate feature in the program which won't affect the modeling. Upload the file you are using and I'll try and find the problem.The driver files we're using are different. Yours has ohm's as being 6, vs. 4 and a couple other diffrences