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#### mmc

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I had measured the woofer and mid driver response separately and combined them using trace arithmetic (A+B) and am puzzled by the results. see attached screen shot. at freq = 212Hz, amplitudes from the graph are:
A=125.1, B=125.5 A+B=98.7db
From my calculation:
A+B=10log(10^(125.1/10)+10^(125.1/10))=128.3db
I had checked severl dips, they all came out to be way too low. Areas without dips seem OK.
what gives?
does anyone know how trace arthmetics is done in REW?
thanks.

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#### jtalden

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The math is correct as it also takes into account the phase of the signal.

If you look at the relative phase of the 2 measurements you summed you will probably see that at the large dips the phase difference is 180 deg.

Also note that, if you are measuring at some distance from the speaker (as at the LP), the phase at these higher frequencies may sometimes be incorrect. One or both of the phase measurement may have been influenced by a reflection rather than the direct wavefront. This will then indicate a dip that is either not there or greatly overstated.

#### mmc

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your are right, the phase is close to 180 apart. I was thinking about that earlier, but did not really want to do vector arithmetic.
thanks.

#### mmc

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did the vector arithmetic, there is a large dip. but I still could not get numerical agreement.
at 212 Hz
from REW 100db at 16 degree
from my calc 115db at 47 degree.

#### jtalden

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JohnM or other experts would need to clarify further.

I think the math manipulation is actually done on the calculated IR and then back calculated to the magnitude and phase and is thus not simply vector addition, but I do not understand the methodology and resulting differences in detail.

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