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I have 2 12ohm resistors for a crossover design that I'm building, but need the end result needs to be 6ohm. Is there a way that I can wire these together to get a 6ohm load. PE did'nt have 6ohm resistors in stock when I bought them so I went this route thinking I could do this. Help is greatly needed. Thanks.

-Bob
 

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Elite Shackster , HTS Moderator Emeritus
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2 12 Ohm resistors in parallel is 6 Ohms. The formula is R1*R2/(R1+R2) = R In this case R1=R2=12 --> 144/24 = 6.

Hope this helps.
 
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